3x^1/3+2x^2/3=5

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Solution for 3x^1/3+2x^2/3=5 equation: 


x in (-oo:+oo)

(2*x^2)/3+(3*x^1)/3 = 5 // - 5

(2*x^2)/3+(3*x^1)/3-5 = 0

(2*x^2)/3+(3*x)/3-5 = 0

2/3*x^2+x-5 = 0

DELTA = 1^2-(-5*2/3*4)

DELTA = 43/3

DELTA > 0

x = ((43/3)^(1/2)-1)/(2/3*2) or x = (-(43/3)^(1/2)-1)/(2/3*2)

x = 3/4*((43/3)^(1/2)-1) or x = -3/4*((43/3)^(1/2)+1)

x in { -3/4*((43/3)^(1/2)+1), 3/4*((43/3)^(1/2)-1) }

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